Actually, I had in mind the Distributive Law mentioned in the link I posted earlier. Isn't 2(2+2) or (2+2)2 each equal to (4+4) = 8, hence as the denominator of 8 the result is 1?
The distributive property certainly applies, but it's important to apply it properly and with the conventions appropriately followed. The distributive property doesn't allow one to short circuit the entire expression.
Your statement: Isn't 2(2+2) or (2+2)2 = (4+4) = 8 is certainly true. However, in the original problem:
8/2(2+2), one must first use the correct order of operations applied appropriately. The division must occur first.
I.e. 8/2(2+2) = 4(2+2) (division and multiplication happen left to right)
Now, applying the distributive property gives: (4*2 + 4*2) = (8+8) = 16
Note that all of these operators are binary. Without parentheses grouping a more complex expression into one operator, only the numbers to the immediate left and right are affected by the operator.
multiplication, division, addition, and subtraction all require a left and a right operand. Exponentiation, also, is a binary operator (5^2). There is a unary operator which looks like subtraction (the minus sign) which, when put in front of a single operand with no left operand, has the effect of negating the operand.
The operands in the original problem for the division are: 8 and 2, not 8 and 2(2+2). So the division is 8/2 not 8/(2*(2+2)). I keep seeing the implication that the denominator in the original expression is 2(2+2). That's incorrect. By the mathematical order of operations, the denominator is 2.
Maybe writing it this way will help those who see fraction bars to see the correct problem:
8/2(2+2) can be correctly rewritten as:
8
--- x (2+2) = 4 x (2 + 2) = 4 x 4 = 16
2
Where the x above is the multiplicative operator and not a variable.
It is incorrect to rewrite the original expression as:
8
--------------
2 x (2+2)