Posted a new article for student pilots, titled "Remembering Correct X-Wind Taxi Technique"
sideways wind blowing directly at either wingtip, no elevator or aileron correction is recommended, and the elevator and ailerons are neutral.
Not quite -- if the wind is 90 degrees right, for example, you put in full crosswind correction on taxi,
and expect to do the same early on the takeoff roll and towards the end of the landing roll.
Not quite -- if the wind is 90 degrees right, for example, you put in full crosswind correction on taxi, and expect to do the same early on the takeoff roll and towards the end of the landing roll.
FWIW, I think maybe a short Bio would be good on your site. As it stands now, I wonder about credibility. Although the material is good, I like to know about who is writing it.
Which direction? Right or left? What if the winds are variable?
Reality is, VERY SELDOM will the wind be straight off a wingtip. When it is, I suppose best guess as to where to place the ailerons.
I have clarified on this forum earlier in answer to a direct question that I am a student pilot yet to solo.
I am no instructor, and I have a disclaimer on my site saying that I do not intend to provide flight instruction.
My site is meant for student pilots like me, who can learn from the same things that I have learned.
If I had a bio worth putting up on my site, I would have.
why do you worry about credibility when you say the material is good? -
No offense, I asked that in jest!
I've found that generally, if you need left crosswind correction on takeoff (aileron deflected up), you'll taxi to/from the runway with the ailerons in that position the entire time.
I guess I don't understand your question, but my point is that a 90 degree crosswind isn't a no deflection mode (as mentioned in the article) -- it's full deflection to keep the unwind side down.
I guess I don't understand your question, but my point is that a 90 degree crosswind isn't a no deflection mode (as mentioned in the article) -- it's full deflection to keep the unwind side down.
In strictly a theoretical 90 degree crosswind, how will the aileron deflection make a difference at taxi speeds? The wind is near parallel to the control surface.
If I look at the diagrams in the POH, they seem to leave the 90 degree crosswind situation not marked, like it is one that requires no elevator/aileron deflection from neutral.
I agree that it seems to be a logical extension of the starting takeoff roll/ending ground roll situation, but would it make any difference at the speed of "brisk walk"?
The airplane responds to air over its surfaces,
Dan
Greg,
That being said, why do you worry about credibility when you say the material is good? - No offense, I asked that in jest!
-- what happens to the wind vector now?
Authority and Experience give you the background from which to critique the material that you glean your information from.
I don't think anything happens to the wind vector. With respect to the center of gravity of the airplane, it stays where it was. The reason is that the wind vector is applied over a much wider front than the length of the airplane, for any relative change in position of the airplane while taxiing to be a factor. Essentially, the length of the airplane is infinitesimal while the slope and width of the wind front are both infinite (straight line parallel to airplane's longitudinal axis - tan 90). So the moving airplane (Vector-A) can and will remain at 90 degrees to the wind (Vector W, which represents wind direction and hence is at 90 degrees to the slope of the wind front) over taxi distances. One can visualize this as the longitudinal axis of the plane being parallel to the wind front, or, in other words, perpendicular to the wind direction.
Vector A and Vector W will add to produce resultant vector which would tend to make the airplane go in a diagonal path, but this resultant will be balanced by the friction vector from the wheels on concrete in normal circumstances; hence the airplane will move straight ahead and not crab.
However, whether the plane crabs or not, as long as its nose is not allowed to yaw, the airplane will continue to present a 90 degree front to the relatively wide wind front.
If your nose is pointed 360, and you're standing still, and you have a 20kt left crosswind, from 270, then the wind is obviously at a 90 degree angle to your nose, and it isn't clear what purpose deflecting the ailerons in either direction will hold, as the wind will flow across them side-to-side.I don't think anything happens to the wind vector...
I am sorry about the vectors, but please break down the scenario into infinitesimal time slots t0, t1, t2... tn separated by arbitrary distances d0, d1, d2... d(n-1), the sum of d1 through d(n-1) being much much less than the width of the wind front, which for argument's sake say is 2 miles.
Now draw the vectors for each position marked by t. Since the wind front is 2 miles long and the airplane is only 26+ feet, you will find that your diagrams are identical over any distance less than or equal to the width of the front. The airplane will be at 90 degrees to the wind in all your diagrams.
This is probably worse than the vectors... I promise to argue no more.
Okay, you're sitting in a car, the car is pointed North, your arm is extended out the passenger's side window, holding a little flag. The car is parked. There's a 5mph breeze coming in from the East, so your flag is flying to the West.... Now draw the vectors for each position marked by t. Since the wind front is 2 miles long and the airplane is only 26+ feet, you will find that your diagrams are identical over any distance less than or equal to the width of the front. The airplane will be at 90 degrees to the wind in all your diagrams...
If you have a 10kt wind from the West, and you're taxiing at 5kts along a taxiway to the North, how should you hold your ailerons?You do not generate significant wind at taxi speeds so there is no additional wind vector to introduce.
If the airplane crabs far enough into the wind you will not slide off the runway. On an icy runway, you might find yourself in a situation where the only way to remain on the runway is by crabbing into the wind.and the airplane will crab and slide off the runway unless you apply aileron correction.
If you have a 10kt wind from the West, and you're taxiing at 5kts along a taxiway to the North, how should you hold your ailerons?
-harry
Neutral, per POH.
The effective crosswind is forward quarter so the controls are held into the wind.
Neutral, per POH.
You generated wind (relative to the car)while you drove the car. You do not generate significant wind at taxi speeds so there is no additional wind vector to introduce.
The situation is quite different during takeoff roll. Not only are you generating an additional wind vector, but the airplane is producing lift, so that the resultant vector of the crosswind and the airplane's movement is less and less balanced by friction between the wheels and concrete, and the airplane will crab and slide off the runway unless you apply aileron correction.
The situation is quite different during takeoff roll. Not only are you generating an additional wind vector, but the airplane is producing lift, so that the resultant vector of the crosswind and the airplane's movement is less and less balanced by friction between the wheels and concrete, and the airplane will crab and slide off the runway unless you apply aileron correction.
My question is why would a student pilot fight so hard against those who actually fly taildraggers????? The world wonders????????????
You generated wind (relative to the car)while you drove the car. You do not generate significant wind at taxi speeds so there is no additional wind vector to introduce.
The situation is quite different during takeoff roll. Not only are you generating an additional wind vector,
but the airplane is producing lift, so that the resultant vector of the crosswind and the airplane's movement is less and less balanced by friction between the wheels and concrete, and the airplane will crab and slide off the runway unless you apply aileron correction.
Neutral, per POH.
Wrong answer. Sorry.
I am sorry about the vectors, but please break down the scenario into infinitesimal time slots t0, t1, t2... tn separated by arbitrary distances d0, d1, d2... d(n-1), the sum of d1 through d(n-1) being much much less than the width of the wind front, which for argument's sake say is 2 miles.
I don't think about it much anymore, it's pretty automatic. But, as a student, the "dive-away/climb-into" reminder seemed to work well enough, even though the books say neutral elevator with a headwind in a nose-gear.