DesertNomad
Pattern Altitude
A friend recently had an engine failure on takeoff (at 300' AGL). They walked away but the Cherokee 6 was totaled. It got me thinking: "how high can I climb and still land straight ahead on the same runway?" I figured my normal (16R) 11,000' runway, elevation 4415', no wind, 37F, altimeter 30.26", typical winter morning conditions at Reno.
My book t/o roll is 1000' so I changed that to 1500' because I am not a test pilot. At my 85kt initial climb speed, a 5 second reaction time uses up 717' and I need 1000' to land and stop.
So 11,000 - 1500 - 717 - 1000 = 7783' (runway I can fly over going up and coming back down).
Assuming an 800fpm climb and 85 knots (143 feet per second) at all times in the air (I could go a bit slower on decent but may not have time to deploy flaps): 7783' / 143 = 54 seconds allowed in a climb or descent.
54/2 = 27 seconds @ 800fpm = 360 feet, or 4775' MSL at Reno.
Does this sound right? Has anyone here done similar calculations?
My book t/o roll is 1000' so I changed that to 1500' because I am not a test pilot. At my 85kt initial climb speed, a 5 second reaction time uses up 717' and I need 1000' to land and stop.
So 11,000 - 1500 - 717 - 1000 = 7783' (runway I can fly over going up and coming back down).
Assuming an 800fpm climb and 85 knots (143 feet per second) at all times in the air (I could go a bit slower on decent but may not have time to deploy flaps): 7783' / 143 = 54 seconds allowed in a climb or descent.
54/2 = 27 seconds @ 800fpm = 360 feet, or 4775' MSL at Reno.
Does this sound right? Has anyone here done similar calculations?