Greetings, all! First post. I'm getting ready to do my flight training, and just picked up an E6B (mechanical). I love my calculators, but man, I can see how this thing can be faster than a calculator when you learn to use it proficiently. Alas, that is the trouble at the moment...I have questions! Many questions.
I found a couple vids on YouTube that helped quite a bit, but for the most part the other vids weren't very clear.
Anyway, one of the questions I came upon was in regards to divot (D=VT Distance = Velocity x Time). For the most part I thought I understood how to use the E6B in these situations, however, it appears that a question came up that left me a little befuddled.
The question gave the following:
Distance: 13 NM
Time: 6.8 mins
The solution that generated the correct result was to align the 8th tick mark past the "60 Rate" (which on other E6Bs is simply depicted with the large triangular pointer) pointer with 13 on the "A" scale. The rate marker then roughly points to "11.5" on the "A" scale; which represent 115 knots.
However, I thought that the "C" scale (hours) could also be used as minutes and seconds. So I aligned 6:48 on the "C" scale (41.25 on the "B" scale) with the "13" on the "A" scale. When I read off the rate at the rate marker, it indicates "19.2".
What have I done wrong? What was my incorrect assumption?
Thanks for your help!
I found a couple vids on YouTube that helped quite a bit, but for the most part the other vids weren't very clear.
Anyway, one of the questions I came upon was in regards to divot (D=VT Distance = Velocity x Time). For the most part I thought I understood how to use the E6B in these situations, however, it appears that a question came up that left me a little befuddled.
The question gave the following:
Distance: 13 NM
Time: 6.8 mins
The solution that generated the correct result was to align the 8th tick mark past the "60 Rate" (which on other E6Bs is simply depicted with the large triangular pointer) pointer with 13 on the "A" scale. The rate marker then roughly points to "11.5" on the "A" scale; which represent 115 knots.
However, I thought that the "C" scale (hours) could also be used as minutes and seconds. So I aligned 6:48 on the "C" scale (41.25 on the "B" scale) with the "13" on the "A" scale. When I read off the rate at the rate marker, it indicates "19.2".
What have I done wrong? What was my incorrect assumption?
Thanks for your help!