RomeoSierra
Filing Flight Plan
- Joined
- Dec 8, 2017
- Messages
- 15
- Display Name
Display name:
Romeo Sierra
Hi,
I am still training and learning how to complete nav logs and having some trouble calculating the top of climb from the limited rate of climb info in the POH.
The POH is very limited in the information it gives since all it gives is the following:
Altitude / Vy speed / Rate of climb fpm
0ft / 62 / 825
1000ft / 62 / 783
3000ft / 62 / 685
5000ft / 62 / 576
and so on...
(sorry about the formatting, couldn't upload a picture of it)
I'm trying to calculate the TOC from an airport at ~600ft up to 3,500ft.
First of all, I've always been taught we climb at 70kts not 62kts but even assuming I climb at 62kts how do I work out the fpm rate?
Would I take the initial climb rate of about half way between 0 and 1000ft, say 800fpm and then what it would be at about 3,500ft, say 670fpm and average the two to get ~735fpm and use that for the entire climb?
Then since climbing 2,900 ft at 735fpm makes a time of about 3m56s (round up to 4 mins) work out the distance travelled is 9.15nm (distance = speed of 62kt x time of 0.15hrs).
Or is there another simpler way of doing this that I'm way over complicating?
I am still training and learning how to complete nav logs and having some trouble calculating the top of climb from the limited rate of climb info in the POH.
The POH is very limited in the information it gives since all it gives is the following:
Altitude / Vy speed / Rate of climb fpm
0ft / 62 / 825
1000ft / 62 / 783
3000ft / 62 / 685
5000ft / 62 / 576
and so on...
(sorry about the formatting, couldn't upload a picture of it)
I'm trying to calculate the TOC from an airport at ~600ft up to 3,500ft.
First of all, I've always been taught we climb at 70kts not 62kts but even assuming I climb at 62kts how do I work out the fpm rate?
Would I take the initial climb rate of about half way between 0 and 1000ft, say 800fpm and then what it would be at about 3,500ft, say 670fpm and average the two to get ~735fpm and use that for the entire climb?
Then since climbing 2,900 ft at 735fpm makes a time of about 3m56s (round up to 4 mins) work out the distance travelled is 9.15nm (distance = speed of 62kt x time of 0.15hrs).
Or is there another simpler way of doing this that I'm way over complicating?